document.write( "Question 113965This question is from textbook Algebra 1 Applications Connections
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\n" ); document.write( "\n" ); document.write( "is parallel to the graph of (5/4)x-3 and passes through the origin?
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Algebra.Com's Answer #82938 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
Let our equation of the lines be \"y%5B1%5D+=+m%5B1%5Dx+%2B+b\", and \"y%5B2%5D+=+m%5B2%5Dx+%2B+b\",\r
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\n" ); document.write( "parallel to the graph of \"y%5B1%5D=%285%2F4%29+x-3\"\r
\n" ); document.write( "\n" ); document.write( "If passes through the origin, passes through the (\"x\",\"y\") =(\"0\",\"0\")\r
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\n" ); document.write( "\n" ); document.write( "So we have:
\n" ); document.write( "Using the slope-intercept form, \"y+=+mx+%2B+b\", where \"m=slope\" and \"b=y-intercept\",
\n" ); document.write( "If the slopes for our lines are \"m%5B1%5D\"( for given line) and \"m%5B2%5D\" (for line we are looking for), then
\n" ); document.write( "we see that the slope \"m%5B1%5D++\" for given line is \"5%2F4\" and \"y-intercept\" is \"-3\"\r
\n" ); document.write( "\n" ); document.write( "we also know that if slopes are the same, the lines are parallel: \"m%5B1%5D+=+m%5B2%5D\"\r
\n" ); document.write( "\n" ); document.write( "so slope \"m%5B2%5D+=5%2F4+\" too\r
\n" ); document.write( "\n" ); document.write( "since the line passes through the origin, passes through the (\"x\",\"y\") =(\"0\",\"0\"), then \"y-intercept+=+0\", or \"b=0\",\r
\n" ); document.write( "\n" ); document.write( "the slope-intercept form of our line will be:\r
\n" ); document.write( "\n" ); document.write( "\"y%5B2%5D+=+%285%2F4%29+x\"\r
\n" ); document.write( "\n" ); document.write( "here is the graph:\r
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Solved by pluggable solver: Solve the System of Equations by Graphing

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\n" ); document.write( " Start with the given system of equations:
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\n" ); document.write( " \"125x%2By=-3\"
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\n" ); document.write( " \"125x%2By=0\"
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\n" ); document.write( " In order to graph these equations, we need to solve for y for each equation.
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\n" ); document.write( " So let's solve for y on the first equation
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\n" ); document.write( " \"125x%2By=-3\" Start with the given equation
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\n" ); document.write( " \"1y=-3-125x\" Subtract \"125+x\" from both sides
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\n" ); document.write( " \"1y=-125x-3\" Rearrange the equation
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\n" ); document.write( " \"y=%28-125x-3%29%2F%281%29\" Divide both sides by \"1\"
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\n" ); document.write( " \"y=%28-125%2F1%29x%2B%28-3%29%2F%281%29\" Break up the fraction
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\n" ); document.write( " \"y=-125x-3\" Reduce
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\n" ); document.write( " Now lets graph \"y=-125x-3\" (note: if you need help with graphing, check out this solver)
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\n" ); document.write( " \"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+-125x-3%29+\" Graph of \"y=-125x-3\"
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\n" ); document.write( " So let's solve for y on the second equation
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\n" ); document.write( " \"125x%2By=0\" Start with the given equation
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\n" ); document.write( " \"1y=0-125x\" Subtract \"125+x\" from both sides
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\n" ); document.write( " \"1y=-125x%2B0\" Rearrange the equation
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\n" ); document.write( " \"y=%28-125x%2B0%29%2F%281%29\" Divide both sides by \"1\"
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\n" ); document.write( " \"y=%28-125%2F1%29x%2B%280%29%2F%281%29\" Break up the fraction
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\n" ); document.write( " \"y=-125x%2B0\" Reduce
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\n" ); document.write( " Now lets add the graph of \"y=-125x%2B0\" to our first plot to get:
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\n" ); document.write( " \"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+-125x-3%2C-125x%2B0%29+\" Graph of \"y=-125x-3\"(red) and \"y=-125x%2B0\"(green)
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\n" ); document.write( " From the graph, we can see that the two lines are parallel and will never intersect. So there are no solutions and the system is inconsistent.

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