document.write( "Question 1196509: I have been struggling with a word problem. The problem is \"Best rentals charges a daily fee plus a milage fee for renting its cars. Mateo was charged $111.00 for 3 days and 300 miles, while Dara was charged $207.00 for 5 days and 600 miles. What does Best Rentals charge per day and per mile?\" \r
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Algebra.Com's Answer #829368 by ikleyn(52786)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "Best rentals charges a daily fee plus a milage fee for renting its cars.
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document.write( "x = charge per day\r\n" );
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document.write( "y = charge per mile.\r\n" );
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document.write( "The problem is described by the system of 2 equations in 2 unknowns\r\n" );
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document.write( "    3x + 300y = 111   (1)    (Mateo case)\r\n" );
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document.write( "    5x + 600y = 207   (2)    (Dara case)\r\n" );
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document.write( "To solve, multiply equation (1) by 2; keep equation (2) as is.  You will get\r\n" );
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document.write( "    6x + 600y = 222   (3)    \r\n" );
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document.write( "    5x + 600y = 207   (4)  \r\n" );
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document.write( "Now subtract equation (4) from equation (3).  You will get\r\n" );
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document.write( "     x        = 222 - 207 = 15     (the terms with y will cancel each other).\r\n" );
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document.write( "Thus charge per day is 15 dollars.                   <<<---===   ANSWER\r\n" );
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document.write( "Now from equation (1)\r\n" );
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document.write( "    3*15 + 300*y = 111,\r\n" );
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document.write( "which gives\r\n" );
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document.write( "    300y = 111 - 45 = 66,   y = 66/300 = 22/100 = 0.22.\r\n" );
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document.write( "So, charge per 1 mile is $0.22, or 22 cents.         <<<---===   ANSWER\r\n" );
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