document.write( "Question 113953: Jack is twice as old as Jill.In 2 years,jack will be 4 times as old as Jill was 9 years ago. How old are they know \n" ); document.write( "
Algebra.Com's Answer #82934 by checkley71(8403)\"\" \"About 
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let Jack's age=2x & Jill's age=x now.
\n" ); document.write( "in 2 years Jack will be (2x+2) years old.
\n" ); document.write( "(x-9) was Jill's age 9 years ago.
\n" ); document.write( "so we have:
\n" ); document.write( "2x+2=4(x-9) or in 2 years Jack will be 4 times as old as Jill was 9 years ago.
\n" ); document.write( "2x+2=4x-36
\n" ); document.write( "2x-4x=-36-2
\n" ); document.write( "-2x=-38
\n" ); document.write( "x=-38/-2
\n" ); document.write( "x=19 years old is Jill's current age.
\n" ); document.write( "seeing as Jack is twice Jill's age then Jack is 2*19=38 years of age.
\n" ); document.write( "proof:
\n" ); document.write( "2*19+2=4(19-9)
\n" ); document.write( "38+2=4*10
\n" ); document.write( "40=40
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