document.write( "Question 113953: Jack is twice as old as Jill.In 2 years,jack will be 4 times as old as Jill was 9 years ago. How old are they know \n" ); document.write( "
Algebra.Com's Answer #82934 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! let Jack's age=2x & Jill's age=x now. \n" ); document.write( "in 2 years Jack will be (2x+2) years old. \n" ); document.write( "(x-9) was Jill's age 9 years ago. \n" ); document.write( "so we have: \n" ); document.write( "2x+2=4(x-9) or in 2 years Jack will be 4 times as old as Jill was 9 years ago. \n" ); document.write( "2x+2=4x-36 \n" ); document.write( "2x-4x=-36-2 \n" ); document.write( "-2x=-38 \n" ); document.write( "x=-38/-2 \n" ); document.write( "x=19 years old is Jill's current age. \n" ); document.write( "seeing as Jack is twice Jill's age then Jack is 2*19=38 years of age. \n" ); document.write( "proof: \n" ); document.write( "2*19+2=4(19-9) \n" ); document.write( "38+2=4*10 \n" ); document.write( "40=40 \n" ); document.write( " \n" ); document.write( " |