document.write( "Question 1196414: The circular sector highlighted has a radius of 6 cm and transforms itself into the lateral surface of a cone after gluing both dotted lines together as represented below:
\n" ); document.write( "https://i.imgur.com/S0yDQc2.png
\n" ); document.write( "a. What is the radius of the cone's base (in cm)
\n" ); document.write( "b. What is the volume of a cone using the lateral surface and base described above?
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Algebra.Com's Answer #829235 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "For simplicity I will leave off the units in my discussion.

\n" ); document.write( "The circular sector is 5/6 of the whole circle. The length of the curved part of the sector is 5/6 of the circumference of a circle with radius 6: \"%285%2F6%29%282pi%29%286%29=10pi\"

\n" ); document.write( "That curved part of the sector becomes the circumference of the base of the cone. The radius of the cone is the circumference of its base, divided by 2pi: \"%2810pi%29%2F%282pi%29=5\"

\n" ); document.write( "ANSWER a. The radius of the base of the cone is 5

\n" ); document.write( "The slant height of the cone is the radius of the sector: 6.

\n" ); document.write( "The radius of the base of the cone is 5; the slant height is 6; the Pythagorean Theorem tells us the height of the cone is \"sqrt%2811%29\".

\n" ); document.write( "The volume of the cone is one-third the area of the base, times the height:

\n" ); document.write( "\"V=%281%2F3%29%28%28pi%29%285%5E2%29%29%28sqrt%2811%29%29\"

\n" ); document.write( "ANSWER b. The volume of the cone is \"%28%2825%2F3%29sqrt%2811%29%29pi\"

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