document.write( "Question 1196419: (-2,1); perpendicular to 3x+y=1 \n" ); document.write( "

Algebra.Com's Answer #829230 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "The line perpendicular to 3x+y = 1 is\r\n" );
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document.write( "    x - 3y = c,      (1)  where c is an arbitrary constant.\r\n" );
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document.write( "To specify the perpendicular line through the point (-2,1), put in equation (1)\r\n" );
document.write( "x= -2,  y= 1.  You will get then\r\n" );
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document.write( "    c = -2 -3*1 = -2 - 3 = -5.\r\n" );
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document.write( "Thus the equation you are seeking for is  x - 3y = -5.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "For more details and other forms of reasoning, see the lesson\r
\n" ); document.write( "\n" ); document.write( " - Equation for a straight line perpendicular to a given line and passing through a given point \r
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