document.write( "Question 1196412: The annual interest on a $14,000 investment exceeds the interest earned on a $7000 investment by $294. The $14,000 is invested at a 0.6% higher rate of interest than the $7000. What is the interest rate of each investment? \n" ); document.write( "
Algebra.Com's Answer #829224 by josgarithmetic(39617)\"\" \"About 
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If simple interest, one year, r the rate as decimal for the part invested for $7000\r
\n" ); document.write( "\n" ); document.write( "Then amount invested at the 14000 is r+0.06.\r
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\n" ); document.write( "\n" ); document.write( "Interest from the $14000 MINUS interest from the $7000 EQUALS $294.\r
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\n" ); document.write( "\n" ); document.write( "\"14000%28r%2B0.006%29-7000r=294\"
\n" ); document.write( "Solve this for r.
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