document.write( "Question 1196386: You measure 21 backpacks' weights, and find they have a mean weight of 45 ounces. Assume the population standard deviation is 8.3 ounces. Based on this, what is the maximal margin of error associated with a 99% confidence interval for the true population mean backpack weight.\r
\n" ); document.write( "\n" ); document.write( "Give your answer as a decimal, to two places\r
\n" ); document.write( "\n" ); document.write( "±
\n" ); document.write( "
\n" ); document.write( " ounces
\n" ); document.write( "

Algebra.Com's Answer #829221 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
sample size = 21
\n" ); document.write( "sample mean = 45
\n" ); document.write( "population standard deviation = 8.3
\n" ); document.write( "sample standard error = 8.3 / sqrt(21) = 1.811208489.
\n" ); document.write( "confidence level = .99
\n" ); document.write( "critical alpha = .01 / 2 = .005.
\n" ); document.write( "critical z-score = plus or minus 2.575829303.
\n" ); document.write( "z-score formula = z = (x - m) / s
\n" ); document.write( "z is the critical z-score.
\n" ); document.write( "x is the critical raw score
\n" ); document.write( "m is the sample mean
\n" ); document.write( "s is the standard error.
\n" ); document.write( "solving for x, you get:
\n" ); document.write( "x1 = z1 * se + 45 = -2.57582903 * 1.811208489 + 45 = 40.3346361.
\n" ); document.write( "x2 = z2 * se + 45 = 2.57582903 * 1.811208489 + 45 = 49.6653639.
\n" ); document.write( "maximum margin of error = (x2 - x1) / 2 = 4.6653639.
\n" ); document.write( "your solution is 4.67 rounded to two decimal places.
\n" ); document.write( "confirmation that the confidence level = 99% is shown below.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );