document.write( "Question 1196327: Find the slope-intercept form of the equation of the line that
\n" ); document.write( "passes through (2, −1) and is parallel to 8x + 3y = 9.
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Algebra.Com's Answer #829110 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "the slope-intercept form of the equation of the line;\r
\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\"\r
\n" ); document.write( "\n" ); document.write( "passes through (\"2\", \"-1\") \r
\n" ); document.write( "\n" ); document.write( "perpendicular to \"8x+%2B+3y+=+9\"\r
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\n" ); document.write( "\n" ); document.write( "first find the slope of given line\r
\n" ); document.write( "\n" ); document.write( "\"8x+%2B+3y+=+9\"\r
\n" ); document.write( "\n" ); document.write( "\"++3y+=+-8x%2B9\"\r
\n" ); document.write( "\n" ); document.write( "\"++y+=+-%288%2F3%29x%2B9%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"++y+=+-%288%2F3%29x%2B3\"\r
\n" ); document.write( "\n" ); document.write( "so, a slope is \"m=-%288%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "recall that parallel lines have same slopes, so the slope of the line perpendicular to given line will be\r
\n" ); document.write( "\n" ); document.write( "\"m=-%288%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "now use given point and a slope to find equation\r
\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\"..........plug in the coordinates of the point (\"2\", \"-1\") and the slope \"m=-%288%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-%28-1%29=-%288%2F3%29%28x-2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y%2B1=-%288%2F3%29%28x-2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y%2B1=-%288%2F3%29x-%28-%288%2F3%29%292\"\r
\n" ); document.write( "\n" ); document.write( "\"y%2B1=-%288%2F3%29x%2B16%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-%288%2F3%29x%2B16%2F3-1\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-%288%2F3%29x%2B13%2F3\"=> your line\r
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