document.write( "Question 113929: -5x+2y=10
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Algebra.Com's Answer #82911 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"-5%2Ax%2B2%2Ay=10\"
\n" ); document.write( " \"1%2Ax-3%2Ay=11\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get -5 and 1 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of -5 and 1 is -5, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by 5 like this:
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\n" ); document.write( " \"1%2A%28-5%2Ax%2B2%2Ay%29=%2810%29%2A1\" Multiply the top equation (both sides) by 1
\n" ); document.write( " \"5%2A%281%2Ax-3%2Ay%29=%2811%29%2A5\" Multiply the bottom equation (both sides) by 5
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"-5%2Ax%2B2%2Ay=10\"
\n" ); document.write( " \"5%2Ax-15%2Ay=55\"
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\n" ); document.write( " Notice how -5 and 5 add to zero (ie \"-5%2B5=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%28-5%2Ax%2B5%2Ax%29%2B%282%2Ay-15%2Ay%29=10%2B55\"
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\n" ); document.write( " \"%28-5%2B5%29%2Ax%2B%282-15%29y=10%2B55\"
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\n" ); document.write( " \"cross%28-5%2B5%29%2Ax%2B%282-15%29%2Ay=10%2B55\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"-13%2Ay=65\"
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\n" ); document.write( " \"y=65%2F-13\" Divide both sides by \"-13\" to solve for y
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\n" ); document.write( " \"y=-5\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"-5%2Ax%2B2%2Ay=10\" to solve for x
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\n" ); document.write( " \"-5%2Ax%2B2%28-5%29=10\" Plug in \"y=-5\"
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\n" ); document.write( " \"-5%2Ax-10=10\" Multiply
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\n" ); document.write( " \"-5%2Ax=10%2B10\" Subtract \"-10\" from both sides
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\n" ); document.write( " \"-5%2Ax=20\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F-5%29%28-5%29%29%2Ax=%2820%29%281%2F-5%29\" Multiply both sides by \"1%2F-5\". This will cancel out \"-5\" on the left side.
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\n" ); document.write( " \"x=-4\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=-4\", \"y=-5\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"-4\", \"-5\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"-5%2Ax%2B2%2Ay=10\"
\n" ); document.write( " \"1%2Ax-3%2Ay=11\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"-5%2Ax%2B2%2Ay=10\" (red) \"1%2Ax-3%2Ay=11\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"-4\",\"-5\"). This verifies our answer.
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