document.write( "Question 1196300: The gas inside the tire has a volume of 20.00 L at a pressure of 5.00 atm. Calculate the pressure of the gas if its volume is reduced to 10.0 at the same temperature. \n" ); document.write( "
Algebra.Com's Answer #829081 by amoresroy(361)\"\" \"About 
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PV = k Pressure multiplied by volume equals some constant k
\n" ); document.write( "where P is the pressure of the gas, V is the volume of the gas, and k is a constant.\r
\n" ); document.write( "\n" ); document.write( "The equation says that the product of pressure and volume is a constant for a given volume of confined gas and this holds as long as the temperature is constant. For comparing the same substance under two different sets of conditions, the law can be usefully expressed as:\r
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\n" ); document.write( "\n" ); document.write( "P1V1 = P2V2 \r
\n" ); document.write( "\n" ); document.write( "Given:
\n" ); document.write( "P1 = 5atm
\n" ); document.write( "V1 = 20.00 liters
\n" ); document.write( "V2 = 10.00 liters
\n" ); document.write( "P2= ?\r
\n" ); document.write( "\n" ); document.write( "Substitute to calculate P2
\n" ); document.write( "5(20) = 10(P2)
\n" ); document.write( "P2 = 100/10
\n" ); document.write( "P2 = 10 atm\r
\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "The pressure of the gas is 10 atm if volume is reduced to 10.0 liters at the same temperature. \r
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