document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1196266>Question 1196266</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Show your solutions: <BR>\n" );
document.write( "A. The pressure of the air on a mountain is 0.978 atm. What will be the pressure in the units of torr? \r<BR>\n" );
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document.write( "B. In a gas mixtures composed of N2 , Ne, He, the partial pressure of N2 is 0.50 atm ,that of Ne is 1.1 atm ,and that of He is 0.80 atm. calculate the mole fraction of each gas.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #829032 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52800)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=829032\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .\r<BR>\n" );
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document.write( "&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;In this post, &nbsp;I will solve/answer part &nbsp;(A), &nbsp;only.\r<BR>\n" );
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document.write( "<U>Definition</U>    &nbsp;&nbsp;&nbsp;&nbsp;(see web-site https://www.torr.com/what-torr )\r<BR>\n" );
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document.write( "<PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\">\r\n" );
document.write( "    The torr (symbol: Torr) is a non-SI unit of pressure defined as 1/760 of an atmosphere. \r\n" );
document.write( "    It was named after Evangelista Torricelli, an Italian physicist and mathematician who discovered \r\n" );
document.write( "    the principle of the barometer in 1644.\r\n" );
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document.write( "&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<U>Solution</U>\r<BR>\n" );
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document.write( "0.978 atm = 0.978*760 = 743.28 torr.\r\n" );
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document.write( "Probably, you herd somewhen, that 1 atm = 960 mm of the mercury column.\r\n" );
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document.write( "So, 1 torr is the pressure corresponding to 1 (one) millimeter of the mercury column.\r\n" );
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document.write( "Therefore, to say that the air pressure is 743.28 torr is the SAME as to say \r\n" );
document.write( "that the air pressure is 743.28 mm of the mercury column.\r\n" );
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document.write( "Solved, &nbsp;answered and explained in full.\r<BR>\n" );
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document.write( "Do not pack more than 1 problem per post&nbsp;: &nbsp;&nbsp;it is prohibited by the rules of this forum.\r<BR>\n" );
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