document.write( "Question 1196272: Find a linear function h, given h(9) = - 39 and h(- 1) = 11. Then find h(5).
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Algebra.Com's Answer #829029 by ikleyn(52786) $\"\"$ $\"About$

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document.write( "On the interval from -1 to 9, which has the length of 10, the function's change is  -39 - 11 = -50.\r\n" );
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document.write( "Hence, the function's slope is  = -5.\r\n" );
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document.write( "So, the function is  \r\n" );
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document.write( "    h(x) - 11 = (-5)*(x - (-1)).\r\n" );
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document.write( "Simplify it step by step\r\n" );
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document.write( "    h(x) - 11 = (-5)*(x+1)\r\n" );
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document.write( "    h(x) = -5x - 5 + 11 = -5x + 6.      <<<---===   it is the answer to the first question.\r\n" );
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document.write( "Then  h(5) = -5*5 + 6 = -25 + 6 = -19.  <<<---===   it is the answer to the second question.\r\n" );
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