document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1196240>Question 1196240</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Larry Mitchell invested part of his $31,000 advance at 5% annual simple interest and the rest at 2% annual simple<BR>\n" );
document.write( "interest. If his total yearly interest from both accounts was $1,430, find the amount invested at each rate.<BR>\n" );
document.write( "The amount invested at 5% is $=<BR>\n" );
document.write( "The amount invested at 2% is $= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #828990 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=828990\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = amount invested at 5% in $<BR>\n" );
document.write( "    31,000 - x = amount invested at 2% in $\r<BR>\n" );
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document.write( "Equation<BR>\n" );
document.write( "  .05x + .02(31,000 - x) = 1,430<BR>\n" );
document.write( "  .05x + 620 - .02x = 1,430<BR>\n" );
document.write( "  .03x = 1,430 - 620<BR>\n" );
document.write( "    x = 810/.03<BR>\n" );
document.write( "    x = 27,000\r<BR>\n" );
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document.write( "Answer:<BR>\n" );
document.write( "The amount invested at 5% is $27,000.<BR>\n" );
document.write( "The amount invested at 2% is $4,000.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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