document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1196226>Question 1196226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a truck can be rented from company a for ​$80 a day plus ​$0.60 per mile. company b charges ​$50 a day plus ​$0.90 per mile to rent the same truck. how many miles must be driven in a day to make the rental cost for company a a better deal than company​ b's? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #828972 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=828972\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let X = number of miles the truck must be driven in a day\r<BR>\n" );
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document.write( "The equation<BR>\n" );
document.write( "80 + 0.6X = 50 + 0.9X\r<BR>\n" );
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document.write( "Combine like terms<BR>\n" );
document.write( "80 - 50 = 0.9X - 0.6X<BR>\n" );
document.write( "30 = 0.3X<BR>\n" );
document.write( "X = 30/0.3\r<BR>\n" );
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document.write( "X = 100 miles\r<BR>\n" );
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document.write( "Answer:<BR>\n" );
document.write( "The truck must be driven at least 100 miles in a day to make the rental cost for Company A a better deal than company​ B's. </SPAN>\n" );
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