document.write( "Question 1196221: (CO 2) Consider the table below.\r
\n" );
document.write( "\n" );
document.write( " Profit Loss Total
\n" );
document.write( "Urban location 50 38 88
\n" );
document.write( "Rural location 61 94 155
\n" );
document.write( "Total 111 132 243\r
\n" );
document.write( "\n" );
document.write( "
\n" );
document.write( "Find the probability that a randomly selected location is in an urban location, given that it is operating a loss.\r
\n" );
document.write( "\n" );
document.write( "Group of answer choices\r
\n" );
document.write( "\n" );
document.write( "55.0%\r
\n" );
document.write( "\n" );
document.write( "48.8%\r
\n" );
document.write( "\n" );
document.write( "36.2%\r
\n" );
document.write( "\n" );
document.write( "28.8% \n" );
document.write( "
Algebra.Com's Answer #828965 by greenestamps(13216) You can put this solution on YOUR website! \n" ); document.write( "Conditional probability: find the probability that a particular location is an urban one, GIVEN THAT it is operating at a loss. \n" ); document.write( "Informally, the \"given that\" means the denominator of the probability fraction is only the number of locations that are operating at a loss: 132 \n" ); document.write( "The numerator of the probability fraction is the number of locations that are operating at a loss and are also rural: 38 \n" ); document.write( "The probability is then 38/132, which is approximately 28.8%. \n" ); document.write( "ANSWER: 28.8% \n" ); document.write( "Formally, the conditional probability is \r\n" ); document.write( " P(operating at a loss AND urban) (38/243)\r\n" ); document.write( " ---------------------------------- = ---------- = 38/132\r\n" ); document.write( " P(operating at a loss) (132/243)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |