document.write( "Question 1196215: Two factory plants are making TV panels. Yesterday, Plant A produced 3000 panels. Ten percent of the panels from Plant A and 3%of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was 6% ?
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Algebra.Com's Answer #828957 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "Two factory plants are making TV panels. Yesterday, Plant A produced 3000 panels.
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document.write( "Let x = How many panels did Plant B produce.\r\n" );
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document.write( "The number of defective panels from plant A is 0.1*3000.\r\n" );
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document.write( "The number of defective panels from plant B is 0.03*x\r\n" );
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document.write( "The total defective panels from both plants is\r\n" );
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document.write( "    0.1*3000 + 0.03x = 0.06*(3000+x).\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    300 + 0.03x = 180 + 0.06x\r\n" );
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document.write( "    300 - 180 = 0.06x - 0.03x\r\n" );
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document.write( "       120    =     0.03x\r\n" );
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document.write( "        x     =     120/0.03 = 4000.\r\n" );
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document.write( "ANSWER.  Plant B produced 4000 panels.\r\n" );
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