document.write( "Question 1196190: a+b+c=3 and a^2 + b^2 +c^2 =3 solve for a^2022 +b^2022 +c^2022 show proof \n" ); document.write( "
Algebra.Com's Answer #828929 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "a+b+c=3 and a^2 + b^2 +c^2 =3 solve for a^2022 +b^2022 +c^2022 show proof \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "I will start the solution from proving another statement\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " +----------------------------------------------+\r\n" ); document.write( " | If 3*(a^2 + b^2 + c^2) = (a+b+c)^2, |\r\n" ); document.write( " | where \"a\", \"b\" and \"c\" are real numbers, |\r\n" ); document.write( " | then a = b = c. |\r\n" ); document.write( " +----------------------------------------------+\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Proof\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From 3*(a^2+b^2+c^2) = (a+b+c)^2, you can easily deduce making FOIL, that\r\n" ); document.write( "\r\n" ); document.write( " 2a^2 + 2b^2 + 2c^2 = 2ab + 2ac + 2bc. (1)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Next, you can re-write and transform (1) in this way\r\n" ); document.write( "\r\n" ); document.write( " (a^2-2ab+b^2) + (a^2-2ac+c^2) + (b^2-2bc+c^2) = 0,\r\n" ); document.write( "\r\n" ); document.write( "or, equivalently,\r\n" ); document.write( "\r\n" ); document.write( " (a-b)^2 + (a-c)^2 + (b-c)^2 = 0. (2)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "But the squares of real numbers are always non-negative, and the sum of non-negative numbers \r\n" ); document.write( "can be equal to 0 (zero) if and only if each of these non-negative numbers is zero.\r\n" ); document.write( "\r\n" ); document.write( "So, we conclude from (2) that a = b = c, and the statement is PROVED.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " +--------------------------------------------------+\r\n" ); document.write( " | Now, let's apply this statement to our case. |\r\n" ); document.write( " +--------------------------------------------------+\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "We are given that a+b+c = 3 and a^2+b^2+c^2 = 3.\r\n" ); document.write( "\r\n" ); document.write( "So, in our case 3*(a^2 + b^2 + c^2) = 3*3 = 9 = 3^2 = (a + b + c)^2.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Thus we can apply this theorem, proved above, to conclude that a = b = c.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Next, since a+b+c = 3, it means that a = b = c = 1.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "And finally, we obtain a^2022 + b^2022 + c^2022 = 1^2022 + 1^2022 + 1^2022 = 1 + 1 + 1 = 3.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. Under given conditions, a^2022 + b^2022 + c^2022 = 3.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It is well known problem of the school Math circle level.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I corrected my typo which was noticed by tutor @math_tutor2020.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thanks for noticing it !\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now you see the corrected version.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |