document.write( "Question 1196168: An object is launched from ground level directly upward at a rate of 144
\n" ); document.write( "feet/sec. The equation for object’s height is
\n" ); document.write( "2
\n" ); document.write( "y x x = − + 16 144
\n" ); document.write( ". What values of x is the
\n" ); document.write( "object at or above a height of 288 feet?
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Algebra.Com's Answer #828881 by Alan3354(69443)\"\" \"About 
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An object is launched from ground level directly upward at a rate of 144
\n" ); document.write( "feet/sec. The equation for object’s height is
\n" ); document.write( "2
\n" ); document.write( "y x x = − + 16 144
\n" ); document.write( ". What values of x is the
\n" ); document.write( "object at or above a height of 288 feet?
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\n" ); document.write( "h(t) = -16t^2 + 144t is a usable equation.
\n" ); document.write( "-16t^2 + 144t = 288
\n" ); document.write( "t^2 - 9t + 18 = 0
\n" ); document.write( "(t-3)*(t-6) = 0
\n" ); document.write( "t = 3 and t = 6 seconds
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