document.write( "Question 1196148: please help with equation for interest
\n" ); document.write( "if a principle of 2000 at rate of 6% earns 300, how much will principle of 4000 earn at 8%?
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Algebra.Com's Answer #828861 by ikleyn(52788)\"\" \"About 
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\n" ); document.write( "please help with equation for interest
\n" ); document.write( "if a principle of 2000 at rate of 6% earns 300, how much will principle of 4000 earn at 8%?
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\n" ); document.write( "\n" ); document.write( "The correct formulation is as follows:\r
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document.write( "    |   If a principal of 2000 at simple annual interest rate of 6%   |\r\n" );
document.write( "    |    earns 300 in some time interval, how much will a principal   |\r\n" );
document.write( "    |          of 4000 earn at 8% simple annual interest rate         |\r\n" );
document.write( "    |                 during the same time interval ?                 |\r\n" );
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document.write( "Use the formula for simple interest \r\n" );
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document.write( "    I = P*r*t,    (1)\r\n" );
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document.write( "P is the principal, t is the time (in years), r is the annual simple interest rate,\r\n" );
document.write( "I is the interest amount.\r\n" );
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document.write( "For the first scenario, we have\r\n" );
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document.write( "    300 = 2000*0.06*t.\r\n" );
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document.write( "From this equation, find time t = \"300%2F%282000%2A0.06%29\" = 2.5 years.\r\n" );
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document.write( "So, the time period is 2.5 years.\r\n" );
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document.write( "Apply the formula (1) AGAIN, this time for the second scenario\r\n" );
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document.write( "    I = 4000*0.08*2.5 = 800.\r\n" );
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document.write( "ANSWER.  The second interest amount is 800.\r\n" );
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\n" ); document.write( "\n" ); document.write( "To see many other similar  (and different)  solved problems on simple interest accounts,  look into the lesson\r
\n" ); document.write( "\n" ); document.write( "    - Simple interest percentage problems \r
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\n" ); document.write( "\n" ); document.write( "Learn the subject from there.\r
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