Algebra.Com's Answer #828831 by ikleyn(52790)![\"\"](\"/images/stars/stars-13.gif\")  
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document.write( "Ibrahim Hussein of Kenya won the 1992 Boston Marathon (a 26-mile race)
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document.write( "in (about) .8 of an hour less than the winner of the first Boston Marathon in 1897,
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document.write( "John J. McDermott of New York. Find each runner's speed, if McDermott's speed was
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document.write( "(about) .73 times Hussein's speed. (Hint: Don't round until the end of the calculations.)
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document.write( "Let x be the speed of Ibrahim Hussein of Kenya in the 1992 Boston Marathon, in miles per hour.\r\n" );
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document.write( "Then the speed of John J. McDermott of New York in the first Maraphon in 1897 is 0.87x mph.\r\n" );
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document.write( "The longer time was  hours (distance divided by the speed).\r\n" );
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document.write( "The shorter time was  hours.\r\n" );
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document.write( "The difference of times was 0.8 of an hour. It gives an equation\r\n" );
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document.write( " - = 0.8 \r\n" );
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document.write( "To solve the equation, multiply both sides by 0.73x. You will get\r\n" );
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document.write( " 26 - 0.73*26 = 0.73*0.8x.\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( " 7.02 = 0.584x\r\n" );
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document.write( " x =  = 12.02054795, or 12.021 miles per hour (rounded).\r\n" );
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document.write( "ANSWER. The speed of Ibrahim Hussein of Kenya in the 1992 Boston Marathon was about 12.021 miles per hour.\r\n" );
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document.write( " The speed of John J. McDermott of New York in the first Maraphon in 1897 was about 0.87*12.021 = 10.458 miles per hour.\r\n" );
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document.write( "Solved.\r
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