document.write( "Question 1196109: The head gardener can mow the lawns in the city park twice as fast as his assistant. Working together, they can complete the job in 1 1/3 hours.
\n" ); document.write( "How long would it take the head gardener working alone?
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Algebra.Com's Answer #828828 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "A slightly different approach:\r
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\n" ); document.write( "\n" ); document.write( "1/3 hr = (1/3)*60 = 60/3 = 20 min
\n" ); document.write( "1 & 1/3 hr = 1 hr + 1/3 hr
\n" ); document.write( "1 & 1/3 hr = 60 min + 20 min
\n" ); document.write( "1 & 1/3 hr = 80 min\r
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\n" ); document.write( "\n" ); document.write( "Consider a lawn that is 900 sq ft. You can replace 900 with any multiple of 3.
\n" ); document.write( "gardener gets 2/3 of that, they get (2/3)*900 = 600 sq ft
\n" ); document.write( "assistant gets 1/3 of that, they get (1/3)*900 = 300 sq ft
\n" ); document.write( "The fractions add to 1, and 2/3 is twice that of 1/3\r
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\n" ); document.write( "\n" ); document.write( "gardener's rate = (600 sq ft)/(80 min)
\n" ); document.write( "gardener's rate = 7.5 sq ft per min\r
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\n" ); document.write( "\n" ); document.write( "Now compute the time needed when the gardener works alone
\n" ); document.write( "rate*time = amount done
\n" ); document.write( "time = (amount done)/(rate)
\n" ); document.write( "time = (900 sq ft)/(7.5 sq ft per min)
\n" ); document.write( "time = 120 min
\n" ); document.write( "time = 2 hours
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