document.write( "Question 1196117: the product of the age of mona and her mother is 546. if her mother is 10 lessb than thrice her age. how old is mona and her mother? \n" ); document.write( "
Algebra.Com's Answer #828823 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "For a quick, informal solution, simply look for two numbers whose product is 546 that satisfy the condition that the larger is 10 less than 3 times the smaller.

\n" ); document.write( "546=6*91=2*3*7*13

\n" ); document.write( "Two combinations look promising: 13 and 42, or 14 and 39. See which one (if either) works.

\n" ); document.write( "3(13)-10 = 39-10 = 29 (not 42); that doesn't work

\n" ); document.write( "3(14)-10 = 42-10 = 32 (not 39); that doesn't work either

\n" ); document.write( "No other combination works either.

\n" ); document.write( "Since age problems must have solutions that are whole numbers, the problem is defective.

\n" ); document.write( "Check to see if you have stated the problem correctly; if not, re-post with the correct information.

\n" ); document.write( "Note if the given information were correct, the setup for an algebraic solution would be easy:

\n" ); document.write( "x = Mona's age
\n" ); document.write( "3x-10 = mother's age

\n" ); document.write( "x(3x-10)=546

\n" ); document.write( "3x^2-10x=546

\n" ); document.write( "3x^2-10x-546=0

\n" ); document.write( "But that quadratic does not factor over the integers....
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