document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1196056>Question 1196056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Walt made an extra $10,000 last year from a part-time job. He invested part of the money at 4% and the rest at 3%. He made a total of $370 in interest. How much was invested at 3%? </SPAN>\n" );
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document.write( "Here is a quick and easy common-sense method for solving \"mixture\" problems like this where the numbers are \"nice\".<br><BR>\n" );
document.write( "(1) All $10,000 invested at 3% would have earned $300 interest; all at 4% would have earned $400.<br><BR>\n" );
document.write( "(2) The actual interest, $370, is 7/10 of the way from $300 to $400.  (300 to 400 is a difference of 100; 300 to 370 is a difference of 70; 70/100 = 7/10.)<br><BR>\n" );
document.write( "Therefore, 7/10 of the total was invested at the higher rate.<br><BR>\n" );
document.write( "ANSWER: 7/10 of $10,000, or $7000, was invested at 4%; the other $3000 at 3%.<br><BR>\n" );
document.write( "CHECK: .04(7000)+.03(3000)=280+90=370<br><BR>\n" );
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