document.write( "Question 1196037: With an average acceleration of -2 m/s2, how long will it take to a cyclist to bring a bicycle with an initial speed of 5 m/s to a complete stop? \n" ); document.write( "
Algebra.Com's Answer #828711 by ikleyn(52906)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "(a)  If the question is \"how long time\", then write the basic equation (like definition) of the acceleration\r\n" );
document.write( "\r\n" );
document.write( "         a = \"%28v%5B2%5D-v%5B1%5D%29%2Ft\",\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "     where \"a\" is the acceleration, t is the time interval, \"v%5B1%5D\"  and  \"v%5B2%5D\" are the velocities \r\n" );
document.write( "     at the beginning and the end of the time interval, respectively.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "     Substitute the given values into equation (1)  a = -2 m/s^2,  \"v%5B2%5D\" = 0 m/s (full stop),  \"v%5B1%5D\" = 5 m/s\r\n" );
document.write( "\r\n" );
document.write( "         -2 = \"%280+-+5%29%2Ft\",  or  -2 = \"%28-5%29%2Ft\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "     It gives  t = \"%28-5%29%2F%28-2%29\" = \"5%2F2\" = 2.5 seconds.     ANSWER\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "(b)  If the question is \"how long distance\", then use the formula \r\n" );
document.write( "\r\n" );
document.write( "         d = \"%28abs%28a%29%2At%5E2%29%2F2\" = \"%282%2A2.5%5E2%29%2F2\" = \"2.5%5E2\" = 6.25 m.    ANSWER\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "     Here 2.5 represents 2.5 s, which is the braking time found above.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );