document.write( "Question 1195997: cos(2\alpha +(\pi )/(4))=3tan(2\alpha +(\pi )/(4)) \n" ); document.write( "
Algebra.Com's Answer #828651 by ikleyn(52802)\"\" \"About 
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document.write( "I read this equation in this way\r\n" );
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document.write( "    \"cos%282%2Aalpha+%2B+pi%2F4%29\" = \"3%2Atan%282%2Aalpha+%2B+pi%2F4%29\".\r\n" );
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document.write( "Notice that the argument under cosine function is the same as under the tangent function.\r\n" );
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document.write( "So, I introduce new variable\r\n" );
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document.write( "    x = \"2%2Aalpha+%2B+pi%2F4\".\r\n" );
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document.write( "Then the given equation takes the form\r\n" );
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document.write( "    cos(x) = 3*tan(x).\r\n" );
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document.write( "It implies\r\n" );
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document.write( "    cos^2(x) = 3*sin(x),\r\n" );
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document.write( "    1-sin^2(x) = 3*sin(x)\r\n" );
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document.write( "    sin^2(x) + 3*sin(x) - 1 = 0\r\n" );
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document.write( "It is a quadratic equation relative sin(x).  Use the quadratic formula\r\n" );
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document.write( "    sin(x) = \"%28-3+%2B-+sqrt%283%5E2-4%2A1%2A%28-1%29%29%29%2F2\" = \"%28-3+%2B-+sqrt%2813%29%29%2F2\".\r\n" );
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document.write( "Since sin(x) must be between -1 and 1, only the root sin(x) = \"%28-3+%2B+sqrt%2813%29%29%2F2\" = 0.30278  really fits.\r\n" );
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document.write( "Hence,  there are two solutions for x:\r\n" );
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document.write( "    x = arcsin(0.30278) = 0.3076  OR  x = \"pi-arcsin%280.30278%29\" = 3.14159 - 0.3076 = 2.834 (rounded).\r\n" );
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document.write( "It gives two solutions for \"alpha\":\r\n" );
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document.write( "    (a)  \"alpha\" = \"%281%2F2%29%2A%280.3076+-+pi%2F4%29\" = \"%281%2F2%29%2A%280.3076-3.14159%2F4%29\" = -0.2389  (rounded);\r\n" );
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document.write( "    (b)  \"alpha\" = \"%281%2F2%29%2A%282.834+-+pi%2F4%29\"  = \"%281%2F2%29%2A%282.834-3.14159%2F4%29\"  =  1.0243  (rounded).\r\n" );
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