document.write( "Question 1195978: A motorist leaves Caribou City at 5:03 am, drives the 163 miles to Mooseville , takes a 36 minute break and then drives a further 328 miles to Shellberg, arriving at 8:11 pm.\r
\n" ); document.write( "\n" ); document.write( "A.) Assuming the motorist drives at a constant speed throughout the journey, at what speed (to the nearest mile per hour) does he/she travel?\r
\n" ); document.write( "\n" ); document.write( "B.) If the motorist had gone 5 miles per hour slower than the speed you recorded in part (a), at what time (to the nearest minute) would he or she arrive?\r
\n" ); document.write( "\n" ); document.write( "C.) If the motorist had gone 1 mile per hour faster than the speed you recorded in part (a), at what time (to the nearest minute) would he or she arrive?
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Algebra.Com's Answer #828640 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
A motorist leaves Caribou City at 5:03 am, drives the 163 miles to Mooseville , takes a 36 minute break and then drives a further 328 miles to Shellberg, arriving at 8:11 pm.
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\n" ); document.write( "Using the 24 hour clock makes finding the difference easier.
\n" ); document.write( "8:11PM = 2011
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document.write( " 2011\r\n" );
document.write( "-0503\r\n" );
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document.write( " 1508, 15 hours 8 minutes\r\n" );
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\n" ); document.write( "There is no advantage to the AM and PM.
\n" ); document.write( "There are disadvantages.
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