document.write( "Question 1195987: Kimani and mwaura live 40km apart.one day kimani left his house at 10:30am and cycled towards mwaura's house at an average speed of 15km/hr.Mwaura left his house at 12:00noon on the same day and cycled towards kimani's houseat an average speed of 25km/hr.determine the distance from kimani's house when the two met
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Algebra.Com's Answer #828637 by math_helper(2461) $\"\"$ $\"About$

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document.write( "Noting that Kimani will travel (15km/hr)*(1.5hrs) = 22.5km  before Mwaura starts, we can write the following, setting t = 0  to be noon:\r
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document.write( "1.  Dk_k(t) = 15t + 22.5
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document.write( "2.  Dk_m(t) = 40 - 25t \r
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document.write( "Where each Dk(t) is distance from Kimani's house.\r
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document.write( "When the two meet, their distances from Kimani's will be equal, so set eq 1 equal to eq 2.   Then solve for t to get t = 0.4375hr\r
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document.write( "At t=0.4375hr,   Dk_k(t) = 15(0.4375) + 22.5 = 6.5625 + 22.5 = 29.0625km\r
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document.write( "Check using Dk_m(t):
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document.write( "    at t=0.4375hr,  Dk_m(t) = 40 - 25(0.4375) = 29.0625km  \n" );
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