document.write( "Question 1195959: A friend spent $19.5 on buying candy. Lollipops cost $0.32 and Hershey kisses cost $0.23
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document.write( "each. If she bought 75 pieces of candy, how many of each type did she buy? \n" );
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Algebra.Com's Answer #828601 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The other tutor showed a solution using a standard formal algebraic method. \n" ); document.write( "A very different method can be used on any 2-part \"mixture\" problem like this which can make it easier to find the answer if the numbers are \"nice\". \n" ); document.write( "In this problem, one kind of candy costs $0.32 each and another costs $0.23 each; and 75 pieces of candy cost $19.50. \n" ); document.write( "Divide the $19.50 by 75 to find the average cost of the pieces of candy is $0.26. \n" ); document.write( "Then, seeing that $0.26 is 1/3 of the way from $0.23 to $0.32, we know that 1/3 of the candies are the more expensive ones. So 75/3 = 25 of the candies are lollipops, leaving 50 for the number of kisses. \n" ); document.write( "ANSWER: 25 lollipops, 50 kisses \n" ); document.write( "CHECK: 25(0.32)+50(0.23)=8.00+11.50 = 19.50 \n" ); document.write( " \n" ); document.write( " |