document.write( "Question 1195934: The second and seventh term of a GP are 18 and 4374 respectively. Find the first term \n" ); document.write( "
Algebra.Com's Answer #828563 by Theo(13342)![]() ![]() You can put this solution on YOUR website! geometric progression formula is An = a * r^(n-1) \n" ); document.write( "when n = 2, the formula becomes A2 = a * r^1 = 18 \n" ); document.write( "when n = 7, the formula becomes A7 = a * r^6 = 4374 \n" ); document.write( "a is the first term in the progression. \n" ); document.write( "solve for a in both terms 2 and 7 to get: \n" ); document.write( "a = 18/r^1 \n" ); document.write( "a = 4374/r^6 \n" ); document.write( "since they both equal a, set the terms equal to each other to get: \n" ); document.write( "18/r^1 = 4374/r^6 \n" ); document.write( "multiply both sides of the equation to r^6 and divide both sides of the equation by 18 to get: \n" ); document.write( "r^6/r^1 = 4374/18 \n" ); document.write( "simplify the left side of the equation to get: \n" ); document.write( "r^5 = 4374/18 \n" ); document.write( "take the fifth root of both sides of the equaion to get: \n" ); document.write( "r = (4374/18)^(1/5) \n" ); document.write( "solve for r to get: \n" ); document.write( "r = 3. \n" ); document.write( "when A2 = 18, the formula becomes: \n" ); document.write( "18 = a * 3^1 = 18 = a * 3 \n" ); document.write( "divide both sides of the equation by 3 to get: \n" ); document.write( "18/3 = a = 6. \n" ); document.write( "when A7 = 4374, the formula becomes: \n" ); document.write( "4374 = a * 3^6 \n" ); document.write( "solve for a to get: \n" ); document.write( "a = 4374/3^6 = 6. \n" ); document.write( "a is the first term in the formula which is equal to 6. \n" ); document.write( "that's your solution. \n" ); document.write( " \n" ); document.write( " |