document.write( "Question 1195929: Four teams A, B, C, and D compete in a tournament, and exactly one of them will
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document.write( "win the tournament. Teams A and B have the same chance of winning the tournament. Team C is
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document.write( "twice as likely to win the tournament as team D. The probability that either team A or team C wins
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document.write( "the tournament is 0.6. Find the probabilities of each team winning the tournament. \n" );
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Algebra.Com's Answer #828551 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "P(A) = x \n" ); document.write( "P(B) = x \n" ); document.write( "P(C) = 2y \n" ); document.write( "P(D) = y \n" ); document.write( "These are the probabilities of each team winning the tournament \n" ); document.write( "The values are such that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Those probabilities add to 1 since they represent 100% of all possible cases. \n" ); document.write( "P(A)+P(B)+P(C)+P(D) = 1 \n" ); document.write( "x+x+2y+y = 1 \n" ); document.write( "2x+3y = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The probability of team A or C winning is 0.6, so, \n" ); document.write( "P(A or C) = P(A) + P(C) ... mutually exclusive \n" ); document.write( "P(A or C) = 0.6 \n" ); document.write( "P(A) + P(C) = 0.6 \n" ); document.write( "x+2y = 0.6 \n" ); document.write( "x = -2y+0.6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Apply substitution \n" ); document.write( "2x+3y = 1 \n" ); document.write( "2( x )+3y = 1 \n" ); document.write( "2( -2y+0.6 )+3y = 1 \n" ); document.write( "-4y+1.2+3y = 1 \n" ); document.write( "-y+1.2 = 1 \n" ); document.write( "-y = 1-1.2 \n" ); document.write( "-y = -0.2 \n" ); document.write( "y = 0.2 \n" ); document.write( "Therefore, P(C) = 2*y = 2*0.2 = 0.4 and P(D) = y = 0.2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And, \n" ); document.write( "x = -2y+0.6 \n" ); document.write( "x = -2(0.2)+0.6 \n" ); document.write( "x = -0.4+0.6 \n" ); document.write( "x = 0.2 \n" ); document.write( "which means P(A) = P(B) = x = 0.2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Summary: \n" ); document.write( "P(A) = 0.2 \n" ); document.write( "P(B) = 0.2 \n" ); document.write( "P(C) = 0.4 \n" ); document.write( "P(D) = 0.2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "P(A)+P(B)+P(C)+P(D) = 1 \n" ); document.write( "0.2+0.2+0.4+0.2 = 1 \n" ); document.write( "1 = 1 \n" ); document.write( "and, \n" ); document.write( "P(A or C) = P(A) + P(C) = 0.2 + 0.4 = 0.6 \n" ); document.write( "The answers are confirmed. \n" ); document.write( " \n" ); document.write( " |