document.write( "Question 1195927: A market research survey in which 60 consumers were contacted states that 65% of all consumers of a certain product were motivated by the product's advertising. Find the confidence limits for the proportion of consumers motivated by advertising in the population, given a confidence level equal to 0.95 \n" ); document.write( "

Algebra.Com's Answer #828548 by Boreal(15235) $\"\"$ $\"About$

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95% half-interval for a proportion is z*sqrt(p(1-p)/n)
\n" ); document.write( "=1.96 sqrt (0.65*0.35/60)
\n" ); document.write( "=0.1207
\n" ); document.write( "the interval is (0.53, 0.77) \n" ); document.write( "

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