document.write( "Question 1195905: A total of $9000 is invested: part at 5% and the remainder at 15%. How much is invested at each rate if the annual interest is $520? \n" ); document.write( "
Algebra.Com's Answer #828528 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Here is an informal method for solving this kind of problem that is fast and easy if the numbers are \"nice\".

\n" ); document.write( "(1) All $9000 invested at 5% would earn $450 interest; all at 15% would earn $1350 interest.
\n" ); document.write( "(2) Perhaps using a number line, look where the actual interest of $520 lies between $450 and $1350: 450 to 520 is a difference of 70; 450 to 1350 is a difference of 900; 520 is 70/900 = 7/90 of the way from 450 to 1350.
\n" ); document.write( "(3) That means 7/90 of the total was invested at the higher rate.

\n" ); document.write( "ANSWER: 7/90 of $9000, or $700, was invested at 15%; the other $8300 at 5%.

\n" ); document.write( "CHECK: .05(8300)+.15(700) = 415+105 = 520

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