document.write( "Question 1195879: Rewrite square root of negative 9 end root minus 6 in complex number notation. \n" ); document.write( "
Algebra.Com's Answer #828479 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Recall that \"i+=+sqrt%28-1%29\" by definition of what it means to be an imaginary number. \r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "\"sqrt%28-9%29+=+sqrt%28-1%2A9%29\"\r
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\n" ); document.write( "\"sqrt%28-9%29+=+sqrt%28-1%29%2Asqrt%289%29\"\r
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\n" ); document.write( "\"sqrt%28-9%29+=+i%2A3\"\r
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\n" ); document.write( "\"sqrt%28-9%29+=+3i\"
\n" ); document.write( "We do not involve the plus/minus in this case. This is because the result of the square root function is one output only.
\n" ); document.write( "Input = -9 leads to output = 3i\r
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\n" ); document.write( "\n" ); document.write( "Therefore,
\n" ); document.write( "\"sqrt%28-9%29+-+6+=+3i+-+6+=+-6%2B3i\"
\n" ); document.write( "The complex number is of the form a+bi
\n" ); document.write( "a = -6 = real part
\n" ); document.write( "b = 3 = imaginary part
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