document.write( "Question 1195851: Historically, 93% of the deliveries of an overnight mail service arrive before 10:30 the following morning. If a random sample of 500 deliveries is selected, what is the probability the sample will have more than 95% of the deliveries arriving before 10:30 the following morning? \n" ); document.write( "
Algebra.Com's Answer #828469 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! This is calculating a z-value which is here z=(phat-p)/sqrt (p*(1-p)/n) \n" ); document.write( "=0.02/sqrt(0.93*0.07/500)\r \n" ); document.write( "\n" ); document.write( "=0.02/0.0114 \n" ); document.write( "=1.75 \n" ); document.write( "Probability z > 1.75 is 0.0398 \n" ); document.write( "- \n" ); document.write( "Can check with a normal approximation \n" ); document.write( "mean is 0.93*500=465 \n" ); document.write( "variance is that *0.07=32.55 \n" ); document.write( "sd is sqrt of that=5.71 \n" ); document.write( "95% of 500 is 475 \n" ); document.write( "so z=(475.5-465)/5.71, using the continuity correction factor \n" ); document.write( "=1.84 and the probability of z> 1.84 is 0.0329. \n" ); document.write( " |