document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1195355>Question 1195355</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is 8 more than twice another. their sum is 62. what are the numbers?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #828460 by </B><A HREF=/tutors/aboutme.mpl?userid=dezbee2008><B>dezbee2008(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dezbee2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dezbee2008><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=828460\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's determine our numbers first\r<BR>\n" );
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document.write( "n = first number<BR>\n" );
document.write( "2n+8 = 8 more than twice the number<BR>\n" );
document.write( "62 = sum of the two numbers\r<BR>\n" );
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document.write( "Put the equation together: n+2n+8=62\r<BR>\n" );
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document.write( "Combine like terms: 3n+8=62\r<BR>\n" );
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document.write( "Subtract 8 from both sides: 3n=54\r<BR>\n" );
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document.write( "Divide 3 by both sides: n=18\r<BR>\n" );
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document.write( "Plug 18 into the original equation: 18+2(18)+8=62\r<BR>\n" );
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document.write( "Solve using order of operations: 18+36+8=62<BR>\n" );
document.write( "54+8=62<BR>\n" );
document.write( "62=62 </SPAN>\n" );
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