document.write( "Question 1195855: Calculate for the surface area of a frustum of a sphere if the diameter of its ends are 80 cm and 120 cm and the thickness is 30 cm. \n" ); document.write( "
Algebra.Com's Answer #828458 by MathLover1(20849)\"\" \"About 
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\"study140122-frustum026245915134941061485\"\r
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\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "the diameter of its ends are: \"80cm\" and \"120cm\" and the thickness is \"30cm\"\r
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\n" ); document.write( "\n" ); document.write( "A=pi(a^2+b^2+2Rh)\r
\n" ); document.write( "\n" ); document.write( "\"a\" is the radius of the smaller base->\"a=80cm%2F2=40cm\"
\n" ); document.write( "\"b\"is the radius of the larger base->\"b=120cm%2F2=60cm\"
\n" ); document.write( "\"R\" is the radius of the sphere
\n" ); document.write( "\"h\" is the difference in height of the two base->\"h=30cm\"\r
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\n" ); document.write( "\n" ); document.write( "As we can see, we first have to determine the radius of the sphere \"R\". We can find the radius from the given base diameters and frustum height.\r
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\n" ); document.write( "\n" ); document.write( "\"R=sqrt%28b%5E2%2B%28b%5E2-a%5E2-h%5E2%29%2F%282h%29%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"R=sqrt%2860%5E2%2B%28%2860%5E2-40%5E2-30%5E2%29%2F%282%2A30%29%29%5E2%29%29\"
\n" ); document.write( "\"R=62.74\"\r
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\n" ); document.write( "\n" ); document.write( "then the area is:\r
\n" ); document.write( "\n" ); document.write( "\"A=pi%2840%5E2%2B60%5E2%2B2%2A62.74%2A30%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A=28162.49cm%5E2\" \r
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