document.write( "Question 1195861: This is a calculus question. Could you explain question 18 on https://www.math.purdue.edu/php-scripts/courses/oldexams/serve_file.php?file=16600FE-F2016.pdf ? I know the answer is D but don't know how to get there. Please attach an image of your work as a reply. \n" ); document.write( "
Algebra.Com's Answer #828447 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "This is a calculus question. Could you explain question 18 on
\n" ); document.write( "https://www.math.purdue.edu/php-scripts/courses/oldexams/serve_file.php?file=16600FE-F2016.pdf ?
\n" ); document.write( "I know the answer is D but don't know how to get there.
\n" ); document.write( "Please attach an image of your work as a reply.
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document.write( "Every/any/each Calculus student knows (or must know - this knowledge is a pre-requisite) that\r\n" );
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document.write( "    ln(1+y) = \"y\" - \"y%5E2%2F2\" + \"y%5E3%2F3\" - \"y%5E4%2F4\" + . . .     (1)\r\n" );
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document.write( "for all real values y, |y| < 1.  It is called  \" the Maclaurin series of  f(y) = ln(1+y) \".\r\n" );
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document.write( "Replace (substitute) here y = -x^2.  You will get\r\n" );
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document.write( "    ln(1-x^2) = \"-x%5E2\" - \"x%5E4%2F2\" - \"x%5E6%2F3\" - \"x%5E8%2F4\" - . . .     (2)\r\n" );
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document.write( "Right side is your series with the sign \"-, minus\".\r\n" );
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document.write( "So, multiply both sides of identity (2) by (-1), and you will get the identity (D), which you need\r\n" );
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document.write( "    \"-ln%281-x%5E2%29\" = \"x%5E2\" + \"x%5E4%2F2\" + \"x%5E6%2F3\" + \"x%5E8%2F4\" + . . .     (3)\r\n" );
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