document.write( "Question 1195857: A stone was thrown from the top of a cliff 60 meters above sea level. The height of the
\n" );
document.write( "stone above sea level t seconds after it was released, is given by H(t) = -5t2 + 20t + 60
\n" );
document.write( "meters.
\n" );
document.write( "a) Find the time it takes for the stone to reach its maximum height.
\n" );
document.write( "b) Find the maximum height above sea level reached by the stone.
\n" );
document.write( "c) How long did it take before the stone struck the water? \n" );
document.write( "
Algebra.Com's Answer #828441 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A stone was thrown from the top of a cliff 60 meters above sea level. The height of the stone above sea level t seconds after it was released, is given by H(t) = -5t^2 + 20t + 60 meters. \n" ); document.write( "--- \n" ); document.write( "a) Find the time it takes for the stone to reach its maximum height. \n" ); document.write( "The max of the quadratic is at t = -b/2a \n" ); document.write( "t = -20/-10 = 2 seconds \n" ); document.write( "-------- \n" ); document.write( "b) Find the maximum height above sea level reached by the stone. \n" ); document.write( "H(2) = -5*4 + 20*2 + 60 = 80 meters \n" ); document.write( "---- \n" ); document.write( "c) How long did it take before the stone struck the water? \n" ); document.write( "--- Poorly worded question. \n" ); document.write( "How many seconds passed from launch to impact? \n" ); document.write( "H(t) = -5t^2 + 20t + 60 = 0 \n" ); document.write( "t^2 - 4t - 12 = 0 \n" ); document.write( "(t-6)*(t+2) = 0 \n" ); document.write( "t = 6 seconds to impact --- ignore the negative solution \n" ); document.write( " \n" ); document.write( " |