document.write( "Question 1191366: Suppose that $2300 is invested at 4.7% annual interest rate, compounded monthly. How much money will be in the account in (A)8 MONTHS and (B)4 years? round to the nearest cent. \n" ); document.write( "
Algebra.Com's Answer #828423 by dezbee2008(5)\"\" \"About 
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We will be using the formula \"A=P%281%2Br%2Fn%29%5Ent\" where:
\n" ); document.write( "A is the total accrued amount
\n" ); document.write( "P is the principle ($2300)
\n" ); document.write( "R is the rate (4.7/100 = 0.047)
\n" ); document.write( "N is the number of times compounded (12 months)
\n" ); document.write( "T is the time (in years, in this case we will use 2/3 for 8 months and 4 for 4 years)\r
\n" ); document.write( "\n" ); document.write( "After 8 Months
\n" ); document.write( "Write the formula: A=P(1+r/n)^nt
\n" ); document.write( "Plug in the numbers: A=$2300(1+.047/12)^(12)(2/3)
\n" ); document.write( "Multiply the exponents: A=$2300(1+.047/12)^8
\n" ); document.write( "Divide the fraction in the parenthesis: A=$2300(1+.0039)^8
\n" ); document.write( "Add in the parenthesis: A=$2300(1.0039)^8
\n" ); document.write( "Solve the exponent: A=$2300(1.0316)
\n" ); document.write( "Finish the problem: A=$2372.68\r
\n" ); document.write( "\n" ); document.write( "After 4 Years
\n" ); document.write( "Write the formula: A=P(1+r/n)^nt
\n" ); document.write( "Plug in the numbers: A=$2300(1+.047/12)^(12)(4)
\n" ); document.write( "Multiply the exponents: A=$2300(1+.047/12)^48
\n" ); document.write( "Divide the fraction in the parenthesis: A=$2300(1+.0039)^48
\n" ); document.write( "Add in the parenthesis: A=$2300(1.0039)^48
\n" ); document.write( "Solve the exponent: A=$2300(1.2054)
\n" ); document.write( "Finish the problem: A=$2774.70
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