document.write( "Question 1195839: Abiodum and Taiwon share 735 sweets between them so that Abiodum get 95 sweets more than Taiwon. Find how many sweets each get? \n" ); document.write( "
Algebra.Com's Answer #828408 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "The solution from the other tutor, using two variables, is fine -- but it requires a lot of extra algebra to reach the solution.

\n" ); document.write( "With the given information in the given form, a solution using a single variable is much easier.

\n" ); document.write( "x = # of sweets that Taiwon gets
\n" ); document.write( "x+95 = # of sweets that Abiodum gets

\n" ); document.write( "The total number of sweets is 735:

\n" ); document.write( "\"x%2Bx%2B95=735\"
\n" ); document.write( "\"2x%2B95=735\"
\n" ); document.write( "\"2x=735-95=640\"
\n" ); document.write( "\"x=640%2F2=320\"

\n" ); document.write( "ANSWERS:
\n" ); document.write( "Taiwon gets x=320 sweets
\n" ); document.write( "Abiodum gets x+95=415 sweets

\n" ); document.write( "And here is an informal solution, using logical reasoning and simple mental arithmetic, that gets the answers using exactly the same path as the formal algebraic solution above:

\n" ); document.write( "(1) Take away the \"extra\" 95 sweets that Abiodum has; that leaves 640 sweets, with equal numbers for both.
\n" ); document.write( "(2) Divide the 640 by 2 to find each of them gets 320; that is Taiwon's share.
\n" ); document.write( "(3) Add the \"extra\" 95 to the 320 that Abiodum gets to get his total of 415.
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