document.write( "Question 1195812: A house was valued at $95,000 in the year 1989. The value appreciated to $170,000 by the year 2001.
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document.write( " A) If the value is growing exponentially, what was the annual growth rate between 1989 and 2001? r = Round the growth rate to 4 decimal places. \r
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document.write( "B) What is the correct answer to part A written in percentage form? r = %.\r
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document.write( " C) Assume that the house value continues to grow by the same percentage. What will the value equal in the year 2006 ? value = $ Round to the nearest thousand dollars. \n" );
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Algebra.Com's Answer #828366 by Boreal(15235) You can put this solution on YOUR website! let 1989 be 0 \n" ); document.write( "t=12 in 2001 \n" ); document.write( "95000(1+r)^12=170000 \n" ); document.write( "(1+r)^12=170000/95000=1.789 \n" ); document.write( "take the 12th root of that value and round at end. \n" ); document.write( "1+r=1.049689 \n" ); document.write( "r=0.0497 or 4.9689%\r \n" ); document.write( "\n" ); document.write( "1.049689^17 (for 2006)=2.28050 \n" ); document.write( "multiply that by 95,000 for the answer $216,647.95 or $217,000 \n" ); document.write( " |