document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1195638>Question 1195638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let S = {1,2,3,...,18,19,20} be the universal set.\r<BR>\n" );
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document.write( "Let sets A and B be subsets of S, where:\r<BR>\n" );
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document.write( "Set A={2,3,5,6,7,11,12,13,14,16,17,19,20}\r<BR>\n" );
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document.write( "Set B={3,6,7,11,13,14,16,17}\r<BR>\n" );
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document.write( "LIST the elements in the set <BR>\n" );
document.write( "A∪B:A∪B= {____ }\r<BR>\n" );
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document.write( "LIST the elements in the set <BR>\n" );
document.write( "A∩B:A∩B= {____}\r<BR>\n" );
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document.write( "Enter the elements as a list, separated by commas. If the result is the empty set, enter DNE </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #828347 by </B><A HREF=/tutors/aboutme.mpl?userid=Solver92311><B>Solver92311(821)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Solver92311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Solver92311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=828347\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "The union of two sets contains elements that are in one set, the other set, or both.  For example:  The Union of A and B contains the element 2 because 2 is an element of A and it contains the element 6 because 6 is an element of both A and B.  The element 1 of the universal set is not an element of A union B because neither A nor B contain the element 1.  Since all of the elements of B are also in A, the union set is identical to A\r<BR>\n" );
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document.write( "The intersection of two sets is the set of elements that are in both of the sets.  For example, the element 2 is not in the intersection because 2 is only in set A, and the element 1 is not in the intersection because 1 is not in either A or B.  Since all of the elements in B are also in A, the intersection set is identical to set B.\r<BR>\n" );
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document.write( "																<BR>\n" );
document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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document.write( "From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> <BR>\n" );
document.write( "I > Ø<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \ \\r\"> </SPAN>\n" );
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