document.write( "Question 1195600: 71% of 111 delegates in a political convention favored changing the rules to restrict the number of potential candidates. What is the 95% confidence interval for the population proportion.\r
\n" ); document.write( "\n" ); document.write( "Give your answers as decimals, to two places.\r
\n" ); document.write( "\n" ); document.write( " _____< p < _____
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Algebra.Com's Answer #828338 by Boreal(15235)\"\" \"About 
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95% half interval is z(SE)=1.96*sqrt(0.6396*0.3604)/111=z*0.0456=0.0893
\n" ); document.write( "Exact SE is sqrt ((71/111)(40/111)/111), but it's the same here.
\n" ); document.write( "the point estimate is 0.6396
\n" ); document.write( "the interval is (0.5503, 0.7289) or (0.55 ,0.73) or 0.55 < p < 0.73
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