document.write( "Question 1195775: find the indicated probabilities. about 30% of U.S. adults are trying to lose weight. you randomly select eight U.S. adults. find the probability that the number of U.S. adults who say they are trying to lose weight is (a) exactly three, (b) at least three, and (c) more than three \n" ); document.write( "
Algebra.Com's Answer #828310 by Boreal(15235)\"\" \"About 
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This is binomial because n is fixed, assume constant probability and independence of random samples.
\n" ); document.write( "a. 8C3*0.3^3*0.7^5=0.2541
\n" ); document.write( "b. look at 0,1,2
\n" ); document.write( "for 0 it is 0.7^8=0.0576
\n" ); document.write( "for 1 it I 8*0.3*0.7^7=0.1977
\n" ); document.write( "for 2 it is 28*0.3^2*0.7^6=0.2965
\n" ); document.write( "The sum of those is 0.5088
\n" ); document.write( "so at least 3 is everything else or 1-0.5088 or 0.4912 .
\n" ); document.write( "c. More than 3 is 0.4912-0.2541, which is exactly 3=0.2371
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