document.write( "Question 1195777: The total annual revenue for a product is given by R(x) = 10,000x-2x^2
\n" ); document.write( "dollars, where x is the number of units sold.
\n" ); document.write( "(a) To maximize revenue, how many units must be sold?
\n" ); document.write( "(b) Find the maximum possible annual revenue?
\n" ); document.write( "

Algebra.Com's Answer #828297 by math_helper(2461)\"\" \"About 
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\n" ); document.write( "R(x) = \"10000x-2x%5E2+\"
\n" ); document.write( "dR/dx = 10000-4x\r
\n" ); document.write( "\n" ); document.write( "At min or max, dR/dx = 0: 10000-4x = 0 ==> x = 2500 units for max revenue.
\n" ); document.write( "You can see this is a max (and not a min) by looking at 2nd deriv. which is -4 ==> concave down ==> critical point is a local maximum.\r
\n" ); document.write( "\n" ); document.write( "Plug in x=2500 into R(x) to get the max revenue. To convince yourself, you should plug in x=2501 and x=2499 to see those R(x) values are less than R(2500). \n" ); document.write( "
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