document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1195592>Question 1195592</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Convert 53 cm/sec to in/min. 1 in = 2.54 cm, 1min = 60 sec. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #828111 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=828111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Convert 53 cm/sec to in/min. 1 in = 2.54 cm, 1min = 60 sec.<BR>\n" );
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document.write( "53 cm = 53 cm*(1 in/2.54 cm) = 53/2.54 inches<BR>\n" );
document.write( "Notice the cms cancel<BR>\n" );
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document.write( "53 cm/sec = 53/2.54 in/sec * 60 sec/1 min = (53/2.54)*60<BR>\n" );
document.write( "Notice the seconds cancel<BR>\n" );
document.write( "= ~1252 in/minute<BR>\n" );
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document.write( "Including the units reduces the chance of multiplying when you should divide and v.v.\r<BR>\n" );
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