document.write( "Question 1195566: Fred’s coffee shop makes a blend that is a mixture of two types of coffee. Type A coffee cost Fred $4.60 per pound, and type B coffee costs $5.70 per pound. This month’s blend used twice as many pounds of type B as type A, for a total cost of $640.00. How many pounds of type A coffee were used? \n" ); document.write( "

Algebra.Com's Answer #828107 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "The other two responses you have received show formal algebraic solutions.

\n" ); document.write( "If formal algebra is not required, you can solve this using logical reasoning and simple calculations. And doing that will give you good mental exercise.

\n" ); document.write( "The number of pounds of coffee of type B is twice the number of pounds of coffee of type A. So the cost of each 3 pounds of coffee is 2($5.70)+1($4.60)=$16; that makes the cost per pound of the mixture $16/3.

\n" ); document.write( "The total cost was $640, so the number of pounds of mixture was

\n" ); document.write( " $\"640%2F%2816%2F3%29=640%283%2F16%29=3%2A40=120\"$

\n" ); document.write( "Since the mixture was 120 pounds, 40 pounds were type A coffee and 80 pounds were type B coffee.

\n" ); document.write( "ANSWER: 40 pounds of type A coffee were used

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