document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1195544>Question 1195544</A>: <I><SPAN STYLE=\"word-break: break-all;\"> HIGHLIGHT ANSWER PLEASE \r<BR>\n" );
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document.write( "A town's population has been growing linearly. In 2003, the population was 59,800 people, and the population has been growing by approximately 3,600 people each year.\r<BR>\n" );
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document.write( "Write the formula for the function  <BR>\n" );
document.write( "P<BR>\n" );
document.write( "(<BR>\n" );
document.write( "x<BR>\n" );
document.write( ")<BR>\n" );
document.write( "  which represents the population of this town  <BR>\n" );
document.write( "x<BR>\n" );
document.write( "  years after 2003.<BR>\n" );
document.write( "P<BR>\n" );
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document.write( "x<BR>\n" );
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document.write( "=<BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <BR>\n" );
document.write( "Use this function to determine the population of this town in the year 2015.<BR>\n" );
document.write( "In 2015, the population will be <BR>\n" );
document.write( " people. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #828060 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=828060\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> straight line equation is y = mx + b<BR>\n" );
document.write( "m is the slope<BR>\n" );
document.write( "b is the y-intercept.<BR>\n" );
document.write( "your equation becomes y = 3600 * x + 59800.<BR>\n" );
document.write( "x = 0 is the year 2003.<BR>\n" );
document.write( "when x = 0, y = 59800.<BR>\n" );
document.write( "when x = 1, y = 59800 + 3500<BR>\n" );
document.write( "when x = 2, y = 59800 + 2 * 3500<BR>\n" );
document.write( "etc.<BR>\n" );
document.write( "the year 2015 is 2015 - 2003 = 12 years after 2003.<BR>\n" );
document.write( "the value of x in 2015 is equal to 12.<BR>\n" );
document.write( "the value of y in 2015 is equal to 59800 + 12 * 3500 = 101800.<BR>\n" );
document.write( "your solutions are:<BR>\n" );
document.write( "the equation is y = 3500 * x + 59800 *****<BR>\n" );
document.write( "the population in 2015 = 101800 *****<BR>\n" );
document.write( "here is a graph of the equation.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2022/071701.jpg\"><BR>\n" );
document.write( "let me know if you have any questions.<BR>\n" );
document.write( "theo\r<BR>\n" );
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document.write( " </SPAN>\n" );
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