document.write( "Question 1195535: Jason forgot that his bicycle was locked up at school, so he ran to the school to get the bicycle, and then rode it back home, his running speed was 9.6kph and his riding speed was 28.8kph, find the distance between his home and school, if the round trip took 20 minutes \n" ); document.write( "
Algebra.Com's Answer #828054 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Observe that his riding speed of 28.8km/hr is exactly 3 times his running speed of 9.6km/hr. Since the distances to and from school are the same, he spent 3 times as long running as riding.

\n" ); document.write( "Then, since the total time was 20 minutes, he spent 15 minutes (1/4 hour) running and 5 minutes (1/12 hour) riding.

\n" ); document.write( "So the distance between his home and school is (1/4)(9.6) = 2.4km, or (1/12)(28.8) = 2.4km.

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