document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1195509>Question 1195509</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bowl is in the shape of a hemisphere (half sphere) with radius 10 cm. The surface of the water in the<BR>\n" );
document.write( "container has a radius of 7 cm. How deep is the water? Give your answer to one decimal place. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #828015 by </B><A HREF=/tutors/aboutme.mpl?userid=bushra444><B>bushra444(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bushra444><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=828015\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The distance from the hemisphere center to the water surface in the bowl is (Pithagoras)  <BR>\n" );
document.write( "\sqrt{10^2-7^2}=\sqrt{100-49}=\sqrt{51}\r<BR>\n" );
document.write( "\n" );
document.write( "Then the depth of the water in the bowl is\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "10-\sqrt{51} = 2.9 cm  (to one decimal place).<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );